محاولتي : f(x)=cos(x)+1/x g(x)=2x+sin(x) السؤال : احسب lim f عند 0 و + الجواب : lim f(x) [x->0+] = + lim f(x) [x->0-] = + lim f(x) [x->+ ] = السؤال : احسب lim g عند /2 و + الجواب : lim g(x) [x-> /2] = lim g(x) [x-> + ] = + https://www.tajribaty.com/forum/viewt...=87&p=262#p262